JEE Advanced2010PhysicsWaves and SoundActual
A hollow pipe of length 0.8 ~m is closed at one end. At its open end a 0.5 ~m long uniform string is vibrating in its second harmonic and it resonates with the fundamental frequency of the pipe. If the tension in the wire is 50 ~N and the speed of sound is 320 ~ms ⁻¹ , the mass of the string is
Options
- A5 ~g
- B10 ~g
- C20 ~g
- D40 ~g
Correct answer
B. 10 ~g
Step-by-step solution
2 ( v₁ 2 l₁ )= v₂ 4 l₂ T / l₁ = 320 4 l₂ ( = mass per unit length of wire) or 50 / 0.5 = 320 4 0.8 Solving we get =0.02 kg m =20 g m Mass of string = (20 g m )(0.5 ~m )=10 ~g The correct option is (b).