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A 20 ~cm long string, having a mass of 1.0 ~g , is fixed at both the ends. The tension in the string is 0.5 ~N . The string is set into vibration using an external vibrator of frequency 100 Hz . Find the separation (in cm ) between the successive nodes on the string.

Correct answer

5

Step-by-step solution

Distance between the successive nodes, aligned d & = 2 = v 2 f & = T / 2 f aligned Substituting the values we get d=5 ~cm

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