JEE Advanced2006PhysicsWaves and SoundActual
A massless rod B D is suspended by two identical massless strings A B and C D of equal lengths. A block of mass ' m ' is suspended point P such that B P is equal to ' x ', if the fundamental frequency of the left wire is twice the fundamental frequency of right wire, then the value of x is
Options
- A1 / 5
- B1 / 4
- C41 / 5
- D31 / 4
Correct answer
A. 1 / 5
Step-by-step solution
f v T Further _p=0 or or f_ A B =2 f_ C D T_ A B =4 T_ C D aligned T_ A B (x) & =T_ C D (l-x) 4 x & =l-x ( as T_ A B -4 T_ C D ) x & = l 5 aligned