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JEE Advanced 2006

Exam: JEE Advanced
Year: 2006
Subject: Physics
Chapter: Waves and Sound

JEE Advanced 2006 · Physics · Waves and Sound

A massless rod B D is suspended by two identical massless strings A...

A massless rod

B D

is suspended by two identical massless strings

A B

and

C D

of equal lengths. A block of mass '

m

' is suspended point

P

such that

B P

is equal to '

x

', if the fundamental frequency of the left wire is twice the fundamental frequency of right wire, then the value of

x

is

A massless rod B D is suspended by two identical massless strings A B and C D of equal lengths. A block of mass ' m '

Options

A $1 / 5$
B $1 / 4$
C $41 / 5$
D $31 / 4$

Correct answer

A. $1 / 5$

Step-by-step solution

f \propto v \propto \sqrt{T}

Further

\Sigma \tau_p=0 or

or f_{A B}=2 f_{C D} \Rightarrow T_{A B}=4 T_{C D}

\begin{aligned}T_{A B}(x) & =T_{C D}(l-x) \\ 4 x & =l-x\left(\text{ as })T_{A B}-4 T_{C D}\right) \\ x & =\frac{l}{5} \end{aligned}

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