15 moles of H ₂ and 5.2 moles of I ₂ are mixed and allowed to attain equilibrium at 773 K . At equilibrium, the number of moles of HI is found to be 10 . The equilibrium constant for the dissociation of HI is

Step-by-step solution

array llll & H ₂+ I ₂ & 2 HI & 15 & 5.2 & 0 equilibrium & 15- x & 5.2- x & 2 x array Let ' V ' is volume in liter Given, 2 x =10x=5 Concentration of H ₂ at equilibrium =15-5 aligned & [ H ₂ ]=10 / V & [ I ₂ ]= 0.2 ~V & [ HI ]= [ 10 v ] aligned aligned & K_c= [ 10 V ]^2 [ 10 V ] [ 0.2 V ] & K_c= 10 10 10 0.2 =50 aligned K _ c ^ for the dissociation of HI is = I K _ c aligned & = 1 50 =0.2 10⁻¹ & =2 10⁻² aligned