At 1000 ~K , the value of K _ c for the below reaction is 10 mol L ⁻¹ . Value of K _ p (in atm) is A ( g ) B ( g )+ C ( g ) (given R =0.082 ~atm ~L ~mol ⁻¹ ~K ⁻¹ )

Step-by-step solution

K_p=K_c(R T)^ n_g aligned & K _ c =10 ~mol ~L ⁻¹, ~T =1000 ~K & R =0.082 ~L ~atm ~mol ⁻¹ ~K ⁻¹ & n _ g =(1+1)-1=1 aligned K_p=(10)(0.082 1000)^1=820