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99 Percentile Qs Bank for JEE MainChemistryIonic Equilibrium

In a saturated solution of the sparingly soluble electrolyte AgIO 3 (molecular mass = 283 ), the equilibrium which sets in is AgIO 3   s ⇌ Ag +   aq + IO 3 -   aq . If the solubility product constant K sp of AgIO 3 at a given temperature is 1 . 0 × 10 - 8 , what is the mass of AgIO 3 in 100   mL of its saturated solution?

Options

  1. A1 . 0 × 10 - 4   g
  2. B28 . 3 × 10 - 2   g
  3. C2 . 83 × 10 - 3   g
  4. D1 . 0 × 10 - 7   g

Correct answer

C. 2 . 83 × 10 - 3   g

Step-by-step solution

AgIO 3 ⇌ Ag +   aq + IO 3 -   aq S S So, K sp = S 2 , or S 2 = 1 . 0 × 10 - 8 , or S = 1 . 0 × 10 - 4   mol   L - 1 = 1 . 0 × 10 - 4 × 283   g   L - 1 , = 1 . 0 × 1 0 - 4 × 283 1000 g mL - 1 , = 1 . 0 × 1 0 - 4 × 283 × 100 1000 g 100 mL , = 28 . 3 × 10 - 4   g 100   mL , = 2 . 83 × 10 - 3   g 100   mL .

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