99 Percentile Qs Bank for JEE MainChemistryIonic Equilibrium
Calculate the molar solubility of calcium hydroxide Ca ( OH )₂ in 0.10 M NaOH solution. The ionic product of calcium hydroxide is 5.5 10⁻⁶ .
Options
- A11 10⁻⁶
- B1
- C5.5 10⁻⁴
- D5.5
Correct answer
C. 5.5 10⁻⁴
Step-by-step solution
Given, Ionic product of Ca ( OH )₂=5.5 10⁻⁶ Concentration of NaOH solution =0.10 M Ionic product of Ca ( OH )₂=5.5 10⁻⁶ or, Ca ( OH )₂= [ Ca ²⁺ ]+2 [ OH ⁻ ] Let, solubility =S gathered Ca ²⁺+2 [ OH ⁻ ] S (2 S)^2 gathered Also, K_ sp =4 S^3 where, K_ sp = solubility product Due to common ion effect, Molar solubility of Ca ( OH )₂= 5.5 10⁻⁶ 0.1 0.1 =5.5 10⁻⁴