99 Percentile Qs Bank for JEE MainChemistryIonic Equilibrium
pH of a buffer solution decreases by 0.02 units when 0.12 ~g of acetic acid is added to 250 ~mL of a buffer solution of acetic acid and potassium acetate at 27^ C . The buffer capacity of the solution is
Options
- A0.1
- B10
- C1
- D0.4
Correct answer
D. 0.4
Step-by-step solution
Buffer capacity, = d C_ HA d_ pH , where, d C_ HA = no. of moles of acid added per litre aligned d_ pH & = change in pH d C_ HA & = moles of acetic acid volume & = 0.12 / 60 250 / 1000 = 1 125 & = 1 / 125 0.02 = 1 2.5 =0.4 aligned