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An aqueous solution of 6 . 3   gram oxalic acid dihydrate is made up to 250   mL . The volume of 0 . 1   N NaOH required to completely neutralize 10   milliLiter of this solution is:

Options

  1. A40   mL
  2. B20   mL
  3. C10   mL
  4. D4   mL

Correct answer

A. 40   mL

Step-by-step solution

We know that the molecular formula of oxalic acid dihydrate is ( COOH ) 2 . 2 H 2 O . As the n-factor of oxalic acid is 2 , the total equivalents of oxalic acid in 250   ml = 2 ( 6 . 3 126 ) = 1 10 Therefore, the total equivalents of oxalic acid dihydrate in 10   ml = 1 10 × 1 250 × 10 As 0 . 1   N   of   NaOH , having volume V is required to neutralize 1 250 equivalents of oxalic acid dihydrate, so, ( 0 . 1 ) V = 1 250 ⇒ V = 1 25   l   = 1 250 × 1000   m

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