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99 Percentile Qs Bank for JEE MainChemistryIonic Equilibrium

The pH of monoacidic weak base is 10.9. Calculate the percent dissociation in 0.02 M solution.

Options

  1. A7.92 %
  2. B3.95 %
  3. C6.25 %
  4. D2.51 %

Correct answer

B. 3.95 %

Step-by-step solution

Monoacidic weak base BOH aligned & BOH _ ( aq ) B _ ( aq ) ⁺+ OH _ ( aq ) ⁻ & C C C & C - & pH =10.9 & pH + pOH =14 & pOH =14-10.9=3.1 & pOH =- ₁₀ [ OH ⁻ ] & [ OH ⁻ ]=10^ - pOH & =10^ -3.1 =10⁻⁴+0.9 & =10⁻⁴ 10^ 0.9 & [ OH ⁻ ]=7.9 10⁻⁴ M & [ OH ⁻ ]= C _ & = 7.9 10⁻⁴ 0.02 & =3.95 10⁻² & % =3.95 10⁻² 100 & =3.95 % aligned

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