99 Percentile Qs Bank for JEE MainChemistryIonic Equilibrium
The heats of neutralization of CH 3 COOH ,   HCOOH ,   HCN   and H 2 S are - 13 . 2 ,   - 13 . 4 ,   - 2 . 9 and - 3 . 8 kcal per equivalent respectively. The correct increasing order of acid strength is
Options
- AHCOOH < CH 3 COOH < H 2 S < HCN .
- BHCN < H 2 S < CH 3 COOH < HCOOH .
- CHCOOH < CH 3 COOH < HCN < H 2 S .
- DCH 3 COOH < H 2 S < HCN < HCOOH .
Correct answer
B. HCN < H 2 S < CH 3 COOH < HCOOH .
Step-by-step solution
Δ H ionisation = Δ H neutralisation experimental - Δ H neutral theoretical Δ H ionisation CH 3 COOH = - 13.20 + 13.75 = 0.55  kcal  mol - 1 Δ H ionisation HCOOH = - 13.40 + 13.75 = 0.35  kcal  mol - 1 Δ H ionisation HCN = - 2.90 + 13.75 = 10.85  kcal  mol - 1 Δ H ionisation H 2 S = - 3.80 + 13.75 = 9.95  kcal  mol - 1 - 13 . 75   kcal   mol - 1 is the standard enthalpy of neutralisation for strong acid or a strong base. Higher the