99 Percentile Qs Bank for JEE MainChemistryIonic Equilibrium
A solution is 0 . 1 M in Cl - and 0 . 001 M in CrO 4 2 - . Solid AgNO 3 is gradually added to it Assuming that the addition does not change in volume and K sp ( AgCl ) = 1 . 7 × 10 - 10 M 2 and K sp Ag 2 CrO 4 = 1 . 9 × 10 - 12 M 3 . Select correct statement from the following:
Options
- AAgCl precipitates first because its K sp is high.
- BAg 2 CrO 4 precipitates first as its K sp is low.
- CAg 2 CrO 4 precipitates first because the amount of Ag + needed is low.
- DAgCl will precipitate first as the amount of Ag + needed to precipitate is low.
Correct answer
D. AgCl will precipitate first as the amount of Ag + needed to precipitate is low.
Step-by-step solution
i   Ag + required to ppt AgCl s Ksp = IP = Ag + Cl - = 1 . 7 × 10 - 10 Ag + = 1 . 7 × 10 - 9 ii   Ag + required to ppt Ag 2 CrO 4 s Ksp = IP = [ Ag + ] 2 CrO 4 - 2 = 1 . 9 × 10 - 12 Ag + = 4 . 3 × 10 - 5 Ag + required to ppt AgCl is low so AgCl will ppt 1 st .