AP EAMCET202316 May 2023Morning ShiftChemistryChemical EquilibriumActual
One mole of PCl ₅( ~g ) was heated in a 1 ~L closed flask at 500 ~K . At equilibrium, 0.1 mole of Cl ₂( ~g ) was formed. What is its K _ p (in atm)? (Given R =0.082 ~L ~atm ~mol ⁻¹ ~K ⁻¹ )
Options
- A2.7 10⁻⁴
- B0.455
- C0.0111
- D90.0
Correct answer
B. 0.455
Step-by-step solution
aligned & K _ c = x ^2 1- x = (0.1)^2 0.9 =0.011 & Thus, K _ p =(0.011)(0.082 500)^ (2-1) & =0.451 . aligned