The area of the region bounded by the curves y=9 x^2 and y=5 x^2+4 (in sq units) is

Step-by-step solution

Intersecting point of y=9 x^2 and y=5 x^2+4 is given by aligned & 4 x^2=4 & x^2=1 & x= 1 & y=9( 1)^2=9 & aligned Hence, intersecting points are ( 1,9) . aligned Required area & =2 ₀^1 [ (5 x^2+4 )- (9 x^2 ) ] d x & =2 ₀^1 (4-4 x^2 ) d x & =2 [4 x- 4 x^3 3 ]₀^1 & =2 (4- 4 3 )-(0-0)=2 8 3 & = 16 3 sq units aligned