The values of a function f(x) at different values of x are as follows Then, the approximate area (in square units) bounded by the curve y=f(x) and x -axis between x=0 and 5 , using the Trapezoidal rule, is

Step-by-step solution

h= difference of two values of x Take value of f(x) as (y₀, y₁, y₂, , y₅ ) Then by Trapezoidal rule Now, _ x₀ ^ x₀+n h f(x) d x= h 2 [ (y₀+y₅ )+2 (y₁+y₂+y₃+y₄ ) ]= 1 2 [(2+27)+2(3+6+11+18)]= 1 2 [29+2 38]= 1 2 (29+76)= 1 2 105=52.5 Approximate area =52.5 sq unit