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99 Percentile Qs Bank for JEE MainMathematicsArea Under Curves

Find the area enclosed between the curves x 2 + y 2 ≤ 9 π 2 and sin ⁡ x   -   y ≥ 0 .

Options

  1. A9 π 3 4
  2. B9 π 3 2
  3. C3 π 3
  4. Dπ 3

Correct answer

B. 9 π 3 2

Step-by-step solution

The given curves are x 2 + y 2 ≤ 9 π 2   and sin x - y ≥ 0 . So, the required area is A = π 3 π 2 / 2 Hence, required area is 9 π 3 2 .

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