The centre of circle inscribed in square formed by the lines x 2 - 8 x + 12 = 0 and y 2 - 14 y + 45 = 0 , is

Step-by-step solution

Given, circle is inscribed in square formed by the lines x 2 - 8 x + 12 = 0 and y 2 - 14 y + 45 = 0 ⇒ x = 6   &   x = 2 and y = 5   &   y = 9 These lines can be plotted as Here A B C D is a square. Hence, the centre of circle inscribed in this square is the point of intersection of diagonals, which is the mid-point of A C or B D = 2 + 6 2 , 5 + 9 2 = 4 , 7 Centre of inscribed circle is 4 , 7