A 1.0 ~L of aqueous solution contains 1 10⁻⁸ M NaBr , 1 10⁻⁸ M NaCl and 1 10⁻⁸ M NaI. To this solution, 1 10⁻¹⁰ M aqueous AgNO ₃ solution is added drop wise. The order of precipitation of Ag X(X= Cl , Br , I ) is aligned & (K_ sp ( AgCl )=1.8=10⁻¹⁰ ; K_ sp ( AgBr )=5 10⁻¹³ ; . & .K_ sp ( AgI )=8.3 10⁻¹⁷ ) aligned

Step-by-step solution

K_ sp of any salt is equal to the multiplication of concentration of its ions. For AgCl Ag ⁺+ Cl ⁻K_ sp = [ Ag ⁺ ] [ Cl ⁻ ]1.8 10⁻¹⁰=10⁻¹⁰ [ Cl ⁻ ] [ Cl ⁻ ]= 1.8 10⁻¹⁰ 10⁻¹⁰ =1.8 Similarly, for AgBr [ Br ⁻ ]= 5 10⁻¹³ 10⁻¹⁰ =5 10⁻³ For AgI I ⁻= 8.3 10⁻¹⁷ 10⁻¹⁰ =8.3 10⁻⁷ Lesser is the concentration of ion, more easily they get precipitated. So, order of precipitation is AgI > AgBr > AgCl