99 Percentile Qs Bank for JEE MainMathematicsDifferentiation
If y=x^ n x+x( x)^ n , then d y d x is equal to
Options
- Ax^ n-1 (1+n x)+( x)^ n-1 [n+ x]
- Bx^ n-2 (1+n x)+( x)^ n-1 [n+ x]
- Cx^ n-1 (1+n x)+( x)^ n-1 [n- x]
- DNone of the above
Correct answer
A. x^ n-1 (1+n x)+( x)^ n-1 [n+ x]
Step-by-step solution
Given, y=x^ n x+x( x)^ n array c d y d x =n x^ n-1 x+x^ n 1 x +x n( x)^ n-1 ( 1 x ) +1 ( x)^ n =x^ n-1 (1+n x)+( x)^ n-1 [n+ x] array