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JEE Main 202126 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Evening Shift
Subject
Chemistry
Chapter
General Principles and Processes of Isolation of Metals

JEE Main 2021 · 26 February · Evening Shift · Chemistry · General Principles and Processes of Isolation of Metals

Match List- I with List- II List- I List- II (a) Sodium Carbonate...

Match List-II with List-IIII

List-II List-IIII
(a) Sodium Carbonate (i) Deacon
(b) Titanium (ii) Castner-Kellner
(c) Chlorine (iii) van-Arkel
(d) Sodium hydroxide (iv) Solvay

Choose the correct answer from the options given below:

Options

  1. A(a)→(i),(b)→(iii),(c)→(iv),(d)→(ii)\left(a\right) \to \left(i\right), \left(b\right) \to \left(iii\right), \left(c\right) \to \left(iv\right), \left(d\right) \to \left(ii\right)
  2. B(a)→(iii),(b)→(ii),(c)→(i),(d)→(iv)\left(a\right) \to \left(iii\right), \left(b\right) \to \left(ii\right), \left(c\right) \to \left(i\right), \left(d\right) \to \left(iv\right)
  3. C(a)→(iv),(b)→(i),(c)→(ii),(d)→(iii)\left(a\right) \to \left(iv\right), \left(b\right) \to \left(i\right), \left(c\right) \to \left(ii\right), \left(d\right) \to \left(iii\right)
  4. D(a)→(iv),(b)→(iii),(c)→(i),(d)→(ii)\left(a\right) \to \left(iv\right), \left(b\right) \to \left(iii\right), \left(c\right) \to \left(i\right), \left(d\right) \to \left(ii\right)

Correct answer

D. (a)→(iv),(b)→(iii),(c)→(i),(d)→(ii)\left(a\right) \to \left(iv\right), \left(b\right) \to \left(iii\right), \left(c\right) \to \left(i\right), \left(d\right) \to \left(ii\right)

Step-by-step solution

(a) Sodium carbonate Na2CO3{Na}_{2}{CO}_{3} & NaHCO3{NaHCO}_{3} are prepared by Solvay process.

(b) Titanium is refined by Van-Arkel process.

Titanium : Van arkel method

Ti+I2⟶T1TiI4(g){T}_{i} + {I}_{2}\overset{T1}{⟶}{T}_{i}\mathop{{I}_{4}}_{\left(g\right)}

TiI4(g)→T2>T1T2TiRefinedtitanium+2I2(g){T}_{i}\mathop{{I}_{4}}_{\left(g\right)}\mathop{\to}_{{T}_{2} > {T}_{1}}^{{T}_{2}}\mathop{{T}_{i}}_{Refinedtitanium} + 2\mathop{{I}_{2}}_{\left(g\right)}

(c) Chlorine is prepared by Deacon process.

Chlorine : Decon's process

HCl+O2⟶CuCl2H2O+Cl2HCl + {O}_{2}\overset{{CuCl}_{2}}{⟶}{H}_{2}O + {Cl}_{2}

(d) Sodium hydroxide is prepared by Castner - Kellner process.

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