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JEE Main202126 Feb 2021Evening ShiftChemistryGeneral Principles and Processes of Isolation of MetalsActual

Match List- I with List- II List- I List- II (a) Sodium Carbonate (i) Deacon (b) Titanium (ii) Castner-Kellner (c) Chlorine (iii) van-Arkel (d) Sodium hydroxide (iv) Solvay Choose the correct answer from the options given below:

Options

  1. Aa → i ,   b → iii ,   c → iv ,   d → ii
  2. Ba → iii ,   b → ii ,   c → i ,   d → iv
  3. Ca → iv ,   b → i ,   c → ii ,   d → iii
  4. Da → iv ,   b → iii ,   c → i ,   d → ii

Correct answer

D. a → iv ,   b → iii ,   c → i ,   d → ii

Step-by-step solution

(a) Sodium carbonate Na 2 CO 3 & NaHCO 3 are prepared by Solvay process. (b) Titanium is refined by Van-Arkel process. Titanium : Van arkel method T i + I 2 ⟶ T 1 T i I 4 g T i I 4 g → T 2 > T 1 T 2 T i Refined   titanium + 2 I 2 g (c) Chlorine is prepared by Deacon process. Chlorine : Decon's process HCl + O 2 ⟶ CuCl 2 H 2 O + Cl 2 (d) Sodium hydroxide is prepared by Castner - Kellner process.

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