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JEE Main201910 Jan 2019Morning ShiftChemistryGeneral Principles and Processes of Isolation of MetalsActual

Hall Heroult's process is given by:

Options

  1. AC r 2 O 3 + 2 A l → A l 2 O 3 + C r
  2. B2 A l 2 O 3 + 3 C → 4 A l + 3 C O 2
  3. CC u 2 + ( a q ) + H 2 ( g ) → C u ( s ) + 2 H + ( a q )
  4. DZ n O + C → C o k e , 1673 Z n + C O

Correct answer

B. 2 A l 2 O 3 + 3 C → 4 A l + 3 C O 2

Step-by-step solution

Hall Heroult's process: At cathode: A l 3 + + 3 e ⊝ → A l At anode: O 2 - + C → C O + 2 e ⊝ Overall reaction: 2 Al 2 O 3 + 3 C → 4 Al + 3 CO 2

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