JEE Main 201910 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 10 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- General Principles and Processes of Isolation of Metals
JEE Main 2019 · 10 January · Morning Shift · Chemistry · General Principles and Processes of Isolation of Metals
Hall Heroult's process is given by:
Hall Heroult's process is given by:
Options
- ACr2O3+2Al→Al2O3+Cr
- B2Al2O3+3C→4Al+3CO2
- CCu2+(aq)+H2(g)→Cu(s)+2H+(aq)
- DZnO+C→Coke,1673Zn+CO
Correct answer
B. 2Al2O3+3C→4Al+3CO2
Step-by-step solution
Hall Heroult's process:
At cathode:
Al3++3e⊝→AlAt anode:
O2−+C→CO+2e⊝Overall reaction:
2Al2O3+3C→4Al+3CO2
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