Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
99 Percentile Qs Bank for JEE MainMathematicsSequences and Series

If (2 4^ 2 k+1 +3^ 3 k+1 =11 t ) and (2 4^ 2 k+3 +3^ 3 k+4 =11 ) ( (p t+3^q ) ), where (k, t Z⁺ ), then ((p, q)= )

Options

  1. A((16,3 k+1) )
  2. B((16,3 k+4) )
  3. C((32,3 k+1) )
  4. D((32,3 k+4) )

Correct answer

A. ((16,3 k+1) )

Step-by-step solution

By verification method, if (k=0 ) Then, (2 4^1+3^1=11 t ) ( 8+3=11 t t=1 ) Now, from the second given relation on putting the values of ((k, t)=(0,1) ), we get ( aligned 2 (64)+81 & =11 (p+3^q ) 128+81 & =11 (p+3^4 ) 11 (p+3^q ) & =209 p+3^q=19 aligned ) Now, from the option (p ) must be 16 and (q=1 ) (=(3 k+1)_ k=0 . ) Hence, option (a) is correct.

Practice Sequences and Series on Quantrex Academy →

More from Sequences and Series

Let = 3+4+8+9+13+14+ upto 40 terms. If ( )^ 1020 is a root of the equation x^2+x-2=0 , (0, 2 ) , then ^2 + 3 ^2 is equal to: 2026The sum 1 + 1 2 (1^2 + 2^2) + 1 3 (1^2 + 2^2 + 3^2) + upto 10 terms is equal to : 2026The value of 1^3 - 2^3 + 3^3 - + 15^3 is: 2026The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8 . If the first term of the A.P. is equal to the common ratio of the G.P. and the 2026For the functions f( ) = ^2 + ^2 , and g( ) = ^2 + ^2 , > > 0 , let _ 0 < < /2 f( ) = _ 0 < < g( ) . If the first term of a G.P. is ( 2 ) , its common ratio is ( 2 ) and the sum of 2026If the sum of the first 10 terms of the series 1 1 + 1^4 4 + 2 1 + 2^4 4 + 3 1 + 3^4 4 + 4 1 + 4^4 4 + is m n , (m, n) = 1 , then m + n is equal to : 2026Let A₁, A₂, A₃, , A₃₉ be 39 arithmetic means between the numbers 59 and 159 . Then the mean of A₂₅, A₂₈, A₃₁ and A₃₆ is equal to : 2026Let the sum of the first n terms of an A.P. be 3n^2 + 5n . Then the sum of squares of the first 10 terms of the A.P. is: 2026 Full Sequences and Series list All 99 Percentile Qs Bank for JEE Main PYQs