At 500 ~K , for the reaction N ₂(g)+3 H ₂(g) 2 NH ₃(g) , the K_p is 0.036 ~atm ⁻² . What is its K_C in L ^2 ~mol ⁻¹ ? (R=0.082 ~L . atom . mol ⁻¹ ~K ⁻¹ ) .

Step-by-step solution

K_p=K_C(R T)^ Δn N ₂(g)+3 H ₂( ~g ) 2 NH ₃(g) aligned n & =2-(3+1)=2-4=-2 K_p & =0.036 (given) aligned 0.036=K_C(0.082 500)⁻² K_C= 0.036 (0.082 500)⁻² =60.516 ~L ^2 ~mol ⁻²