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JEE Main 20146 April
Exam
JEE Main
Year
2014
Date
6 April
Subject
Chemistry
Chapter
General Principles and Processes of Isolation of Metals

JEE Main 2014 · 6 April · Chemistry · General Principles and Processes of Isolation of Metals

Which series of reactions correctly represents the chemical...

Which series of reactions correctly represents the chemical relations related to iron and its compound?

Options

  1. AFe→diluteH2SO4FeSO4→H2SO4,O2Fe2(SO4)3→heatFeFe\overset{dilute{H}_{2}{SO}_{4}}{\to}{FeSO}_{4}\overset{{H}_{2}{SO}_{4}, {O}_{2}}{\to}{Fe}_{2}{\left({SO}_{4}\right)}_{3}\overset{heat}{\to}Fe
  2. BFe→O2,heatFeO→diluteH2SO4FeSO4→heatFeFe\overset{{O}_{2}, heat}{\to}FeO\overset{dilute{H}_{2}{SO}_{4}}{\to}{FeSO}_{4}\overset{heat}{\to}Fe
  3. CFe→Cl2,heatFeCl3→heat,airFeCl2→ZnFeFe\overset{{Cl}_{2}, heat}{\to}{FeCl}_{3}\overset{heat, air}{\to}{FeCl}_{2}\overset{Zn}{\to}Fe
  4. DFe→O2,heatFe3O4→CO,600℃FeO→CO,700℃FeFe\overset{{O}_{2}, heat}{\to}{Fe}_{3}{O}_{4}\overset{CO, 600 ℃}{\to}FeO\overset{CO, 700 ℃}{\to}Fe

Correct answer

D. Fe→O2,heatFe3O4→CO,600℃FeO→CO,700℃FeFe\overset{{O}_{2}, heat}{\to}{Fe}_{3}{O}_{4}\overset{CO, 600 ℃}{\to}FeO\overset{CO, 700 ℃}{\to}Fe

Step-by-step solution

This is the blast furnace reaction. (Fe→diluteH2SO4FeSO4→H2SO4,O2Fe2(SO4)3→heatFe)\left(\text{Fe}\overset{dilute{H}_{2}{SO}_{4}}{\to}{FeSO}_{4}\overset{{H}_{2}{SO}_{4}, {O}_{2}}{\to}{Fe}_{2}{\left({SO}_{4}\right)}_{3}\overset{heat}{\to}Fe\right) and \left(\text{Fe}\overset{{O}_{2}, heat}{\to}FeO\overset{dilute{H}_{2}{SO}_{4}}{\to}{FeSO}_{4}\overset{heat}{\to}Fe\right)cannotbetheanswersince,cannot be the answer since,{FeSO}_{4}onheatinggiveson heating givesFeOandand{SO}_{2}.<br/><br/>(Fe→Cl2,heatFeCl3→heat,airFeCl2→ZnFe).<br /><br />\left(Fe\overset{{Cl}_{2}, heat}{\to}{FeCl}_{3}\overset{heat, air}{\to}{FeCl}_{2}\overset{Zn}{\to}Fe\right) is wrong because FeCl3{FeCl}_{3}, on heating in air, stays as Fe+3{Fe}^{+ 3} and does not form FeCl2{FeCl}_{2}.
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