A body falls on a surface of coefficient of restitution 0.6 from a height of 1 ~m . Then the body rebounds to a height of

Step-by-step solution

As the body falls from a height array ll & u =0 & v ^2= u ^2+2 gh & v ^2=2 9.8 1=19.6 & v = 19.6 ~m / s array Coefficient of restitution e = v u aligned e & = Velocity after collision ( v _ f ) Velocity before collision ( v _ b ) v _ f & = e v _ b v _ f & =0.6 19.6 ~m / s aligned After the body rebounds, aligned & v^2=u^2-2 g h & u^2=2 g h aligned h = u ^2 / 2 ~g . Here, u = v _ f aligned h & = (0.6 19.6 )^2 2 9.8 & =0.36 ~m aligned