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99 Percentile Qs Bank for JEE MainPhysicsCenter of Mass, Momentum and Collision

The figure shows the positions and velocities of two particles. If the particles move under the mutual attraction of each other, then the position of the centre of mass at t = 1   sec is x   m . The value of x is

Correct answer

6

Step-by-step solution

According to the question, Let A be the object of mass 1   kg and moving in positive x -direction with 5   m   s - 1 and B be the object of mass 1   kg and moving in negative x -direction with 3   m   s - 1 . Now, let x 1 and x 2 be the positions of objects A and B after 1   sec . We know that v   =   S t , where, v is the velocity, S is the displacement, t is the time. ∴   x 1 = 2   m + 5   m   s - 1 × 1   sec = 7   m , x 2 = 8 &

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