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A rod of length 80 ~cm rotates about its mid point with a frequency of 10 rev / s . The potential difference (in volts) between two ends of the rod due to a magnetic field, B=0.5 ~T directed perpendicular to the rod is

Options

  1. A1.6
  2. B2
  3. C0.8

Correct answer

B. 2

Step-by-step solution

Given, frequency of revolution of the rod, f=10 rev / s , length of rod, L=80 ~cm =0.8 ~m and magnetic field B=0.5 ~T Since, rod is rotated about its mid point, hence radius of circular revolution, r= L 2 = 0.8 2 =0.4 ~m Potential difference between centre of rod and one end of rod due to revolution in magnetic is given by aligned V^ & = induced emf = change in flux time taken B . r^2 T & =B . r^2 . f [ f= 1 T ] & =0.5 (0.4)^2 10 & =0.8 aligned Potential difference between two ends of rod due to revolution in the m

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