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A conducting rod P Q of length 1 ~m is moving with a uniform speed 2 ~ms ⁻¹ in a uniform magnetic field of 4 ~T which is directed into the paper. A capacitor of capacity 10 F is connected as shown in the figure. Then, the charge on the plates of the capacitor are

Options

  1. Aq_A=+80 C , q_B=-80 C
  2. Bq_A=-80 C , q_B=+80 C
  3. Cq_A=+1.25 C , q_B=1.25 C
  4. Dq_A=-1.25 C , q_B=+1.25 C

Correct answer

A. q_A=+80 C , q_B=-80 C

Step-by-step solution

Charge on each plate should be aligned & q=C V & V=v B l & q=C(v B l) & =10 10⁻⁶ 2 4 1 & q=80 C & aligned where, So, charges on plates are 80 C .

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