99 Percentile Qs Bank for JEE MainPhysicsElectromagnetic Induction
The magnetic field of an electromagneticwave obeys the relation in a certain region is B=10¹² (5 10^6 t ) T , where t is the time. Then, the induced emf, in a 300 tums in coil of area 20 ~cm ^2 oriented perpendicular to the field is
Options
- A-2 10⁻⁵ (5 10^6 t ) V
- B-3 10⁻⁶ (5 10^6 t ) V
- C-2.5 10⁻⁶ (5 10^6 t ) V
- D-3.3 10⁻⁶ (5 10^6 t )
Correct answer
B. -3 10⁻⁶ (5 10^6 t ) V
Step-by-step solution
Given, B=10⁻¹² (5 10^6 t ) T , N=300 turns and area, A=20 ~cm ^2=20 10⁻⁴ ~m ^2 Hence, the emf induced aligned & e=-N d d t =-N d(B A) d t =-A N d B d t & e=-20 10⁻⁴ 300 d d t (10⁻¹² 5 10^6 t ) & e=6000 10⁻⁴ 10⁻¹² ( 5 10^6 t ) 5 10^6 & e=-3 10⁻⁶ (5 10^6 t ) V aligned Hence, the correct option is (2).