Consider a parallel plate capacitor which is maintained at potential 200 ~V . The separation distance between the plates of capacitor and the area of plates are 1 ~mm and 20 ~cm ^2 , respectively. Calculate displacement current in 1 s .

Step-by-step solution

Displacement current, aligned I_d & = ₀ d d t = ₀ t & = ₀ E A t ( =E A) aligned = ₀ V A t d ( E= V d ) Here, V=200 ~V , aligned t & =1 s =10⁻⁶ ~s , d & =1 ~mm =1 10⁻³ ~m and A & =20 ~cm ^2=20 10⁻⁴ ~m ^2 aligned aligned I_d & = 8.85 10⁻¹² 200 20 10⁻⁴ 10⁻⁶ 10⁻³ & =3.5 10⁻³ ~A =3.5 ~mA aligned