When two different materials A and B having atomic number ${Z}_{1}$ and ${Z}_{2}$ are used as the target in Coolidge $\gamma$ -ray tube at different operating voltage ${V}_{1}$ and ${V}_{2}$ respectively their spectrums are found as below.

The correct relation is

Question

When two different materials A and B having atomic number

{Z}_{1}

and

{Z}_{2}

are used as the target in Coolidge

\gamma

-ray tube at different operating voltage

{V}_{1}

and

{V}_{2}

respectively their spectrums are found as below.

When two different materials A and B having atomic number Z _ 1 and Z _ 2 are used as the target in Coolidge γ -ray

When two different materials A and B having atomic number Z _ 1 and Z _ 2 are used as the target in Coolidge γ -ray

The correct relation is

Quantrex Academy · Accepted Answer

Correct answer: D. V _ 1 > V _ 2 and Z _ 1 < Z _ 2

λ _ = (hc)/(eV) ⇒ λ ∝ (1)/(V) ∵ λ _ 2 > λ _ 1 (see graph) ⇒ V _ 1 > V _ 2 f = a (Z - b) Moseley's law f∝ (Z - 1) ^ 2 ⇒ λ ∝ 1 (Z - 1) ^ 2 ( ∵ f ∝ (1)/(λ) ) λ _ 1 > λ _ 2 (see graph for characteristic lines) ⇒ Z _ 2 > Z _ 1

When two different materials A and B having atomic number Z _ 1 and...

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