Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
99 Percentile Qs Bank for JEE MainPhysicsElectrostatics

Three charges − q 1 , + q 2 and − q 3 are placed as shown in the figure. The x − component of the force on − q 1 is proportional to

Options

  1. Aq 2 b 2 - q 3 a 2 cos θ
  2. Bq 2 b 2 + q 3 a 2 sin θ
  3. Cq 2 b 2 + q 3 a 2 cos θ
  4. Dq 2 b 2 - q 3 a 2 sin θ

Correct answer

B. q 2 b 2 + q 3 a 2 sin θ

Step-by-step solution

Force on ( − q 1 ) due to q 2 = q 1 q 2 4 π ε 0 b 2 ∴ F 1 = q 1 q 2 4 π ε 0 b 2 along q 1 q 2 Force on - q 1 due to - q 3 = ( q 1 ) ( q 3 ) 4 π ε 0 a 2 F 2 = q 1 q 3 4 π ε 0 a 2 as shown F 2 > makes an angle of 90 0 - θ with q 1 q 2 Resolved part of F 2 along q 1 q 2 = F 2 cos 90 0 − θ = q 1 q 3 sin θ 4 π ε 0 a 2 along q 1 q 2 ∴ Total force on − q 1 = [ q 1 q 2 4 π ε 0 b 2 + q 1 q 3 sin θ 4 π ε 0 a 2 ] along x-axis ∴ x-component of force ∝ [ q 2 b 2 + q 3 a 2 sin θ ] .

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

Two charges Q₁ = q and Q₂ = mq are placed at the points P₁(a, b) and P₂(ma, mb) , respectively, in the XY plane, where a, b 0 and m 0, 1 . If V₁ is the potential at a point in the 2026Consider an electric dipole comprising two charges +q and -q each with mass m , separated by a fixed distance d and initially at rest with its dipole moment pointing along i . A un 2026Two point charges q₁=3 , C and q₂=-4 , C are placed at points (2 i +3 j +3 k ) and ( i + j + k ) respectively. Force on charge q₂ is ________ N. ( Take 1 4 ₀ = 9 10^9 SI Units ) 2026The electric potential as a function of x, y is given by V = 5(x^2 - y^2) V. The electric field at a point (2, 3) m is __________ V/m. 2026A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb. If the magnitude of the electric field at centre of the half ring is 100 V/m, then the value 2026A three coulomb charge moves from the point (0, -2, -5) to the point (5, 1, 2) in an electric field expressed as E = 2x i + 3y^2 j + 4 k N/C. The work done in moving the charge is 2026A particle of charge q and mass m is projected from origin with an initial velocity v = ( v₀ 2 x + v₀ 2 y ) . There exists a uniform magnetic field B = B₀ z and a space varying ele 2026A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an electric field E ₁=E₀ x . If another electric field E ₂=2E₀( y + z ) is introduced to the s 2026 Full Electrostatics list All 99 Percentile Qs Bank for JEE Main PYQs