99 Percentile Qs Bank for JEE MainPhysicsElectrostatics
A uniformly charged spherical shell of radius R carries a uniform charge density of σ per unit area. It is made of two hemispherical shells, held together by pressing them with force F . F is proportional to
Options
- A1 ε 0 σ 2 R 2
- B1 ε 0 σ 2 R
- C1 ε 0 σ 2 R
- D1 ε 0 σ 2 R 2
Correct answer
A. 1 ε 0 σ 2 R 2
Step-by-step solution
The electrostatic pressure at a point on the charged conducting surface of surface charge density σ is d F d A = σ 2 2 ε 0 Due to the electrostatic repulsion between the charged hemisphere, there is a requirement of an external force F on each hemisphere which will balance the electrostatic force due to the other hemisphere. For the given case, consider a thin ring at an angle θ away from the diametrical axis. Now lets take a small ring of angle d θ around this ring, as shown in the figure