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99 Percentile Qs Bank for JEE MainPhysicsGravitation

Four particles, each of mass M move along a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is

Options

  1. AGM R
  2. B2 2 GM R
  3. CGM R 1 + 2 2
  4. D1 2 GM R 1 + 2 2

Correct answer

D. 1 2 GM R 1 + 2 2

Step-by-step solution

F = F 1 = F 2 = GM 2 2 R 2 F 3 = GM 2 4 R 2 ∴ F Total towards center = 2 2 F + F 3 = 2 2 GM 2 4 R 2 + GM 2 4 R 2 = GM 2 4 R 2 2 2 + 1 F T = F CP GM 2 4 R 2 2 2 + 1 = M​v 2 R ∴ v = GM 4 R 2 2 + 1

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