99 Percentile Qs Bank for JEE MainPhysicsMagnetic Effects of Current
A particle of specific charge q m = π C kg - 1 is projected from the origin towards positive x-axis with a velocity of 10 m s - 1 in a uniform magnetic field B → = - 2 k ^ T . The velocity v → of the particle after time t = 1 12 s will be (in m s - 1 )
Options
- A5 i ^ + 3 j ^
- B5 3 i ^ + j ^
- C5 3 i ^ - j ^
- D5 i ^ + j ^
Correct answer
B. 5 3 i ^ + j ^
Step-by-step solution
Time period, T = 2 π m qB = 2 π π × 2 = 1 s Thus, the particle will be at point P after t = 1 1 2 s v → = 1 0 cos 3 0 i ^ + sin 3 0 j ^ v → = 1 0 3 2 i ^ + 1 2 j ^ = 5 3 i ^ + j ^ m s - 1