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99 Percentile Qs Bank for JEE MainPhysicsMagnetic Effects of Current

Two infinitely long straight wires A and B , each carrying current I are placed on x and y -axis, respectively. The current in wires A and B flow along - i and j directions respectively. The force on a charged particle having charge q , moving from position, r =d( i + j ) with velocity v = v is

Options

  1. A₀ f v^ 2 ^ j
  2. B₀ f q v ^ j
  3. C₀ f Q v 2 k
  4. D0

Correct answer

B. ₀ f q v ^ j

Step-by-step solution

The given situation for two current carrying wires are shown in the figures. Position vector of charge particle, r =d( i + j )=d i +d j The magnetic field intensity due to the wire along - i direction, B ₂= ₀ 2 Y d (- k ) Similarly, magnetic field intensity due to wire along j direction. B ₂= ₀ 2 r d (- k ) Resultant magnetic field at point P due to both the wires, aligned & B = B ₂+ B ₂=2 ₀ 2 Y d (- k ) & B = ₀ I d (- k ) aligned Force on the charged particles, F =q( v B )=q [v i ₀ Y d (- k ) ]= ₀ Y q V d j

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