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99 Percentile Qs Bank for JEE MainPhysicsMagnetic Effects of Current

Find the magnitude of the magnetic field at the center of an equilateral triangular loop of side length 1 m which is carrying a current of 10 A . (Take μ 0 = 4 π × 10 - 7 NA - 2 )

Options

  1. A18 μ T
  2. B1 μ T
  3. C9 μ T
  4. D3 μ T

Correct answer

A. 18 μ T

Step-by-step solution

Magnetic field due to wire BC is ⇒ B = μ 0 4 π i ℓ × 2 3 3 2 + 3 2 ⊗ Net magnetic field at centre = 3 B = μ 0 4 π i ℓ × 2 3 3 2 + 3 2 3 ⊗ = μ 0 4 π 1 ℓ 6 ( 1 ) 3 = 10 - 7 × 10 1 × 18 = 18 × 10 - 6 T

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