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A 10 coil of 180 turns and diameter 4 ~cm is placed in a uniform magnetic field so that the magnetic flux is maximum through the coil's cross-sectional area. When the field is suddenly removed a charge of 360 C flows through a 618 galvanometer connected to the coil, find the magnetic field.

Options

  1. A12 ~T
  2. B6 ~T
  3. C1 ~T
  4. D8 ~T

Correct answer

C. 1 ~T

Step-by-step solution

Given, resistance of a coil, R=10 number of turns in the coil, N=180 and diameter of the coil =4 ~cm =4 10⁻² ~m Magnetic flux associated with the coil is maximum. Hence, =0^ Magnetic flux, =B A When magnetic field is suddenly removed, then some charge flows through the galvanometer. Given, resistance of a galvanometer, R_g=618 and charge flowing through the galvanometer, q=360 C =360 10⁻⁶ C As q=I t q= e R_ e q t= t t R_ e q ( e=N t ) So, for N turns, q= N R_ eq Here, R_ e q =R+R_g Putting the given values, we get

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