A cubical block of side 10   cm floats at the interface of oil and water. The pressure above that of the atmosphere at the lower face of the block is

Step-by-step solution

We know that the absolute pressure at a depth h in a liquid of density ρ is given as P = P 0 + h ρ g where P 0 = Atmospheric pressure. Therefore, the pressure at the lower face of the block P = P 0 + ρ 1 g h 1 + ρ 2 g h 2 ⇒     P - P 0 = ρ 1 g h 1 + ρ 2 g h 2 ⇒   ∆ P =   600 10 0 . 1 + 1000 10 0 . 02 ⇒     ∆ P =   800   N   m - 2