Two objects suspended from the arms of a balance are in equilibrium when completely submerged in water. The mass of one body is 36 g and its density is 9 g cm - 3 ​. If the mass of the other object is 48 g , then its density in g cm - 3 is

Step-by-step solution

Apparent weight = V ρ - σ g = m ρ ρ - σ g where m = mass of the body, ρ = density of the body and σ = density of water If two bodies are in equilibrium then their apparent weight must be equal. ∴ m 1 ρ 1 ρ 1 - σ g = m 2 ρ 2 ρ 2 - σ g ⇒ 3 6 9 9 - 1 = 4 8 ρ 2 ρ 2 - 1 g . By solving we get ρ 2 = 3 .