A solid float such that its (1 / 3) rd part is above water surface. Then, the density of solid is

Step-by-step solution

Given that, ( 1 3 ) rd part of body is above the water surface. Volume of body outside the water = 1 3 (volume of body) V_o= 1 3 V Volume of body inside, V_i=V-V₀=V- V 3 = 2 V 3 Let mass of body =M Density of body = Density of water, =10^3 ~kg ~m ⁻³ According to the law of floatation, body will float into the liquid (water) when weight of body is balanced by Buoyant force. W=F_B M g=V_i g gathered V g=V_i g V =V_i = V_i V gathered Substituting the values, we get aligned & = 2 V 3 V & = 2 3 10^3= 2000 3 ~kg ~m ⁻³ al