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JEE Main
Exam
JEE Main
Subject
Physics
Chapter
Mechanical Properties of Solids

JEE Main · Physics · Mechanical Properties of Solids

The length of an elastic string is a metres when the longitudinal...

The length of an elastic string is aa metres when the longitudinal tension is 4 N4 \mathrm{~N} and bb metres when the longitudinal tension is 5 N5 \mathrm{~N}. The length of the string in metres when the longitudinal tension is 9 N9 \mathrm{~N} is

Options

  1. Aa−ba-b
  2. B5b−4a5 b-4 a
  3. C2b−14a2 b-\frac{1}{4} a
  4. D4a−3b4 a-3 b

Correct answer

B. 5b−4a5 b-4 a

Step-by-step solution

Let the initial length of the string be " ??. Tension ∝\propto Elongation of the string T1T2=a−lb−l⇒45=a−lb−l4b−4l=5a−5ll=5a−4b Again, T1T3=a−lx−l\begin{aligned} \frac{T_1}{T_2} & =\frac{a-l}{b-l} \Rightarrow \frac{4}{5}=\frac{a-l}{b-l} \\ 4 b-4 l & =5 a-5 l \\ l & =5 a-4 b \\ \text { Again, } \quad \frac{T_1}{T_3} & =\frac{a-l}{x-l}\end{aligned}\begin{aligned} & x=\text { length of the string at tension } T(=9 \mathrm{~N}) \\ & \qquad \begin{aligned} \frac{4}{9} & =\frac{a-(5 a-4 b)}{x-(5 a-4 b)} \\ \frac{4}{9} & =\frac{-4 a+4 b}{x-(5 a-4 b)} \Rightarrow \frac{4}{9}=\frac{4(-a+b)}{x-(5 a-4 b)} \\ \Rightarrow x-(5 a-4 b) & =9 a+9 b \\ x & =-9 a+9 b+5 a-4 b \\ & =5 b-4 a\end{aligned}\end{aligned}$
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