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The Young's modulus of the material of wire is 2 × 10 10 N m - 2 . If the elongation strain is 1% , then the energy stored in the wire per unit volume in J m - 3 is

Options

  1. A10 6 J m - 3
  2. B10 8 J m - 3
  3. C2 × 10 6 J m - 3
  4. D2 × 10 8 J m - 3

Correct answer

A. 10 6 J m - 3

Step-by-step solution

Per unit volume energy stored = 1 2 × Y × strain 2 = 1 2 × Y × l L 2 given l = L × 1 % or l = L 100 Thus per unit volume energy stored = 1 2 × 2 × 10 10 × L 100 L 2 = 10 6 J m - 3

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