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JEE Main
Exam
JEE Main
Subject
Physics
Chapter
Mechanical Properties of Solids

JEE Main · Physics · Mechanical Properties of Solids

The potential energy U between two molecules as a function of the...

The potential energy UU between two molecules as a function of the distance XX between them has been shown in the figure. The two molecules are

The potential energy U between two molecules as a function of the distance X between them has been shown in the figure.

Options

  1. ARepelled when xx lies between AA and BB and are repelled when xx lies between BB and C.C .
  2. BAttracted when xx lies between BB and CC and are repelled when xx lies between AA and B.B .
  3. CAttracted when they reach& B.B .
  4. DRepelled& when they reach& B.B .

Correct answer

B. Attracted when xx lies between BB and CC and are repelled when xx lies between AA and B.B .

Step-by-step solution

Force in terms of variation of potential energy is given by& F=-dUdx\text{F=-}\dfrac{dU}{dx}.

dUdx\dfrac{dU}{dx}in potential energy-displacement curve is slope of the curve.

In AB region slope is negative, hence force will be positive which means repulsive force in nature.

In BC region slope is positive, hence force will be negative which means attractive force in nature.

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