A 50 kg girl wearing high heel shoes balances on a single heel. The...

Given, mass of girl (m) = 50 kg

Diameter of circular heel (2r) = 1.0 cm

Radius (r) = 0.5 cm

= 5 × 10^-3 m

Area of the circular heel (A) = πr²

= 3.14 × (5 × 10^-3)² m²

$= 78 . 50 \times {10}^{- 6}m^{2}$

The pressure exerted on the horizontal floor

$\text{p} = \dfrac{\text{F}}{\text{A}} = \dfrac{\text{mg}}{\text{A}}$

$= \dfrac{\text{50} \times \text{9.8}}{\text{78.50} \times {10}^{- 6}}$

$= 6 . 24 \times {10}^{6}Pa$