A stone is thrown vertically upward. When the particle is at a height half of its maximum height, its speed is 10 m s - 1 , then the maximum height attained by the particle is [ g = 10 m s - 2 ]

Step-by-step solution

Let h be the maximum height to be attained by stone The velocity with which particle is thrown u = 2 gh v 2 =   u 2 – 2 g H When H = h 2 ,   u = 2 g h ,   v = 1 0   m   s - 1 1 0 0 = 2 gh - 2 g h 2 ⇒ h = 1 0   m