A body is released from a great height falls freely towards the earth. Another body is released from the same height exactly a second later. Then the separation between two bodies, 2 s after the release of the second body is, nearly

Step-by-step solution

s = u t + 1 2 a t 2 For Ist body u = 0 a n d a = g f r e e l y f a l l i n g b o d y Distance covered in 2 s, s 1 = 0 + 1 2 g 3 2 For IInd body Distance covered in 2 s, s 2 = 0 + 1 2 g 2 2 ∴ s 1 - s 2 = 1 2 g 3 2 - 2 2 = 1 2 g 9 - 4 = 25 m