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99 Percentile Qs Bank for JEE MainPhysicsMotion in One Dimension

The position coordinates of a particle moving in X - Y as a function of time t are x = 2 t 2 + 6 t + 25 y = t 2 + 2 t + 1 The speed of the object at t = 10 s is approximately

Options

  1. A31 units
  2. B51 units
  3. C71 units
  4. D81 units

Correct answer

B. 51 units

Step-by-step solution

Given, x = 2 t 2 + 6 t + 25 a n d y = t 2 + 2 t + 1 ∴ d x d t = 4 t + 6 a n d d y d t = 2 t + 2 A t t = 10 s d x d t = 4 10 + 6 = 46 a n d d y d t = 2 10 + 2 = 22 v = d x d t 2 + d y d t 2 = 46 2 + 22 2 ≃ 51 units

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