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99 Percentile Qs Bank for JEE MainPhysicsMotion in One Dimension

A particle moving in x - y plane starts from the origin at t =0 with an initial velocity (- i + j ) ms ⁻¹ and undergoes an acceleration of (6 i +4 j ) ms ⁻² . It's displacement after 2 ~s is

Options

  1. A17.32 ~m
  2. B14.14 ~m
  3. C12.42 ~m
  4. D10 ~m

Correct answer

B. 14.14 ~m

Step-by-step solution

We have aligned & x =(-1 2)+ 1 2 6 2^2=-2+12=10 ~m & y =(1 2)+ 1 2 4 2^2=2+8=10 ~m & So, . r |_ t =2 sec =10 i +10 j & | r |= 10^2+10^2 =10 2 ~m & =14.14 ~m aligned

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