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99 Percentile Qs Bank for JEE MainPhysicsMotion in One Dimension

A motor-bike starts from rest, attains a velocity of 10 ~m / s with an acceleration of 0.5 ~m / s ^2 , travels 10 ~km with this uniform velocity and then comes to halt with a uniform deceleration of 0.2 ~m / s ^2 . The total time of travel is

Options

  1. A1070 s
  2. B1050 s
  3. C1150 s
  4. D1170 s

Correct answer

A. 1070 s

Step-by-step solution

The given situation of entire motion of motor bike is shown in the figure. If time taken by the motorbike to reach from point A to B is t_ A B , then for A to B , v_A=0, v_B=10 ~ms ⁻¹, a=0.5 ~ms ⁻² From equation, v=u+a t aligned v_B & =v_A+a t_ A B 10=0+0.5 t_ A B t_ A B & = 10 0.5 =20 ~s aligned Since, motorbike moves from point B to C with constant velocity. Hence, time taken to travel distance B C is given as t_ B C = B C v_B = 10 ~km 10 ~ms ⁻¹ = 10000 ~m 10 ~ms ⁻¹ =1000 ~s For motion of motorbike from point C t

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